Hi dears,

As SSC CGL 2016 cancellation CASE IS DISMISSED AT SUPREME COURT.

and a notice regarding ssc cgl 2017 exam is already posted at NR office the time has come to prepare for the country's most crowded exam.

Here are some

I will try to post daily 25 questions of maths and their solutions.

Why

Let's start maximum time 8 minutes.

As SSC CGL 2016 cancellation CASE IS DISMISSED AT SUPREME COURT.

and a notice regarding ssc cgl 2017 exam is already posted at NR office the time has come to prepare for the country's most crowded exam.

Here are some

**Prev****ious years ques****tion for****SS****C****CGL**exam 2017.I will try to post daily 25 questions of maths and their solutions.

Why

**PREVIO****US****YEARS QUE****STIONS**are necessary to be done? Because ssc do repeat 90% of the question from previous years papers. Hardly 2-3 question are new in ssc exam.Let's start maximum time 8 minutes.

1. Find the ratio of the area of an equilateral triangle of side 2a units to that of a square whose diagonal is 4a units.

(A) 1:1

(B) 2:1

(C) √3:1

(D)√3:8

(B) 2:1

(C) √3:1

(D)√3:8

Ans:-D

Solution- diagonal of square is 4a then its core woupd be 4a/√2 tjat is 2√2a

Now pit in formulas you will get the solution. (√3/4 ×core² is formula for equilateral triangle)

2. A right prism has a triangular base with perimeter 38 cm. If the lateral surface area of the prism is 342 cm², find its height.

(A) 5 cm

(B) 16 cm

(C) 12 cm

(D) 9 cm

(A) 5 cm

(B) 16 cm

(C) 12 cm

(D) 9 cm

Ans:-D

Lateral surface area of prizm is , perimeter×height with this formula we get 9cm answer

3. Find the area of the square inscribed in a circle of radius 6 cm.

(A) 36 cm²

(B) 144 cm²

(C) 72 cm²

(D) 144/√2 cm²

(A) 36 cm²

(B) 144 cm²

(C) 72 cm²

(D) 144/√2 cm²

Ans:-C

If a square is inscribed in circle , circle's diameter would be its diagonal by this we get diagonal 12cm and by solving fore core's length we get 6√2cm now it is easy to solve .

4. If the radius of a sphere increases by 50% then its volume will increase by

(A) 50%

(B) 150%

(C) 337.5%

(D) 237.5%

(A) 50%

(B) 150%

(C) 337.5%

(D) 237.5%

Ans:-D

Let volume is 100 now according to question radius is increased by 50% in the formula of sphere radius is revised 3 time so 50% increases 3 times like this

100---150-----225----337.5 . Final volume-intial volume is the increased part.

5. PXY and PQR are secants drawn to a circle. If PX = 2PQ, XY = 12 cm and PQ = 4 cm, find QR.

(A) 20 cm

(B) 26 cm

(C) 36 cm

(D) 16 cm

(A) 20 cm

(B) 26 cm

(C) 36 cm

(D) 16 cm

Ans:-C

6. A solid rectangular box of dimensions 16 cm × 12 cm ×11 cm is melted to form lead balls of diameter 4 cm. Find the number of balls thus formed.

(A) 52

(B) 100

(C) 93

(D) 63

(A) 52

(B) 100

(C) 93

(D) 63

Ans:-D

When something is melted the volume of that thing never changes, by equalling volume we the answer

7. Find the total surface area and volume respectively of a rectangular box which is 9m long, 8m wide and 7m high.

(A) 391m², 292m³

(B) 382m², 504m³

(C) 504m², 382m³

(D) 121m², 392m³

(A) 391m², 292m³

(B) 382m², 504m³

(C) 504m², 382m³

(D) 121m², 392m³

Ans:-B

Solution is just follow the formula you will get if not than comment down.

8. A 200-m-long train crosses a pole in 10 seconds. Another train travelling at the same speed crosses a 300-m-long platform in 20 seconds. Find the time taken by the second train to cross the first, if the first train is stationary.

(A) 20 seconds

(B) 15 seconds

(C) 10 seconds

(D) 30 seconds

(A) 20 seconds

(B) 15 seconds

(C) 10 seconds

(D) 30 seconds

Ans:-B

200m in 10second means 20m/s right! In 20seconds train would cover 400m hope you get it. Means 100m is length of second train. Now second train will cover 300mbat the speed of 20m/s so the answer is 15seconds.

9. A man rows a distance of 6 kilometres in 45 minutes with the help of the tide. When the direction of the tide reverses he travels another 16 km in 4 hours. How many hours would he have saved, had the direction of the tide not changed?

(A) 4 hours

(B)1½ hours

(C) 2 hours

(D)2⅔ hours

(A) 4 hours

(B)1½ hours

(C) 2 hours

(D)2⅔ hours

Ans-C;

Let the speed of the man be M and that of the tide be T. Then Speed in favourable direction(M + T) = 6/45m = 8 kmph Speed in unfavourable direction (M – T)= 16/4 = 4 kmph Now, M + T = 8, M – T = 4 So, M = 6 kmph and T = 2 kmphNow, favourable time = 8-6 = 2 hours

10. Tap P can fill a tank in 20 hours and Tap Q can fill the same tank in 30 hours. Both taps were opened simultaneously at 6 am and after some time Q was closed. If the tank got filled at 9 pm, at what time was Q closed?

(A) 6 pm

(B) 12 : 30 pm

(C) 7 : 30 pm

(D) 1 : 30 pm

(A) 6 pm

(B) 12 : 30 pm

(C) 7 : 30 pm

(D) 1 : 30 pm

Ans:-D

Q is stopped but P opened for full time that is 15 hours efficiency of P is 3 so total filled by P is 3×15=45 , rest part 15 is filled by Q , Q'efficiency is 2 that means 7:30 hours it kept opened so total time is 6+7:30 is 1:30PM

This is the first post on the series

*of***PRE****VIOUS****YEARS****QUESTIONS FOR SSC CPO,****CGL****2017.****thank you**
Mark wise break up of the post is

Marks 2-3 | you need to do clear the basics with the help of NCERT books

Marks 4-7 | you are average at maths, don't worry practicing these questions will make you best at math

Marks 8-9 | yours math is good but hardly 2-3 topic i.e. chapters are not prepared.

Marks 10 | you have strong hold on maths . Find time to write something for us.

I hope you all will get 10 marks in these previous years questions