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BASIC TRIGONOMETRY QUESTIONS FOR SSC
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These questioins are for those who were either not so good in the secondary classess maths or who are not in touch with the following concepts from 4-5.
As I said these questions are Basic . But some questions are asked by ssc in previous years examination.
Question 1-
Express the following angles in radian measure and centesimal measure :
a]45°
b]20°35'
c] 50°38'40"
Solutions:-
the term ["] is called as seconds & the term ['] is called as minute
as we know 180°= π radian.
1 degree is equal to = π/180
45°ℝℙ= 45*π/180= π/4
solution 1]b.
35' = 35/60 hour now, 20+35/60= 247/12 degree
now change in radian 247/12*π/180= 1235/54 grad.
solution 1]c.
40"=40/60minutes now 38+40/60=116/3min.
after converting minutes in hours 116/180 , add all now 50+116/180=2279/45 degree , Now change it to radian , 2279/45*π/180=2279/7290
Question - 2
One angle of a triangle is 54 degree and another is π/4 radian. Find the third angle in centesimal unit i.e. degree
Solution no-2
angle A=54, angle B= π/4rad.
angle B=45degree
total measures of a triangle is 180 degree so to get remaining i.e. third angle We subsctract the sum of Both from 180 degree Ans. 180- 99= 81 degree
Value of 1 rad=57°16'22"
Question no-3
Find the values of
a)sin2295°
b)tan 1500°
c)tan405°
d)sin225°
Solutions.........
a) sin2295°= sin(6*360° +135°) { easy way to get this is to divide by 360° i.e. 2295/360°}
as last day On 27 apr., 2017 i have explained in my post in the first quadrants all the trignometric identities are postive,
Note:- we only take which is left i.e. 135°
sin(135°)= sin (180-45)= sin 45° Ans.......
b.) tan1500°=tan (4*360°+60°)
tan60°
Now you are able to solve c,d of it.
SOME OF THE SSC'S MOST IMPORTANT PREVIOIUS YEARS IDENTITIES.
QUESTION NO- 4
find the value of
Sin(22½)=?
Let θ= 22+1/2
2θ=45
take Cos both the sides
i.e. Cos2θ=cos45
1/√2=1-2sin²22½ {let sin 22½= X)
now 2x²=1-1/√2
by soving it we get the value ,
Question no- 5
Find the value of
sin15
sin75
hints 15 can be written as 45-30
and 75 can be written as 45+30
SO friends thease are the basic question on trigonometry which is being asked in ssc directly of indirectly. trigonometry is vast it can not be done in a day.
THANK YOU KEEP VISITING KEEP LEARNING AFTER THAT TEACH YOUR EXPERIENCE TO THE ONE WHO'S NEEDY OF IT.
As I said these questions are Basic . But some questions are asked by ssc in previous years examination.
Question 1-
Express the following angles in radian measure and centesimal measure :
a]45°
b]20°35'
c] 50°38'40"
Solutions:-
the term ["] is called as seconds & the term ['] is called as minute
So, we need to do is that term second should be in minute & the term minute should be in hour (because ° is counted in hour)solution - 1] a.
as we know 180°= π radian.
1 degree is equal to = π/180
45°ℝℙ= 45*π/180= π/4
solution 1]b.
35' = 35/60 hour now, 20+35/60= 247/12 degree
now change in radian 247/12*π/180= 1235/54 grad.
solution 1]c.
40"=40/60minutes now 38+40/60=116/3min.
after converting minutes in hours 116/180 , add all now 50+116/180=2279/45 degree , Now change it to radian , 2279/45*π/180=2279/7290
Question - 2
One angle of a triangle is 54 degree and another is π/4 radian. Find the third angle in centesimal unit i.e. degree
Solution no-2
angle A=54, angle B= π/4rad.
angle B=45degree
total measures of a triangle is 180 degree so to get remaining i.e. third angle We subsctract the sum of Both from 180 degree Ans. 180- 99= 81 degree
Value of 1 rad=57°16'22"
Question no-3
Find the values of
a)sin2295°
b)tan 1500°
c)tan405°
d)sin225°
Solutions.........
a) sin2295°= sin(6*360° +135°) { easy way to get this is to divide by 360° i.e. 2295/360°}
as last day On 27 apr., 2017 i have explained in my post in the first quadrants all the trignometric identities are postive,
Note:- we only take which is left i.e. 135°
sin(135°)= sin (180-45)= sin 45° Ans.......
b.) tan1500°=tan (4*360°+60°)
tan60°
Now you are able to solve c,d of it.
SOME OF THE SSC'S MOST IMPORTANT PREVIOIUS YEARS IDENTITIES.
QUESTION NO- 4
find the value of
Sin(22½)=?
Let θ= 22+1/2
2θ=45
take Cos both the sides
i.e. Cos2θ=cos45
1/√2=1-2sin²22½ {let sin 22½= X)
now 2x²=1-1/√2
by soving it we get the value ,
if there were cos instead of sin we can change the sign i.e. "+"
Question no- 5
Find the value of
sin15
sin75
hints 15 can be written as 45-30
and 75 can be written as 45+30
SO friends thease are the basic question on trigonometry which is being asked in ssc directly of indirectly. trigonometry is vast it can not be done in a day.
THANK YOU KEEP VISITING KEEP LEARNING AFTER THAT TEACH YOUR EXPERIENCE TO THE ONE WHO'S NEEDY OF IT.
- Get link
- Other Apps
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