These questioins are for those who were either not so good in the secondary classess maths or who are not in touch with the following concepts from 4-5.

As I said these questions are Basic . But some

Express the following angles in radian measure and centesimal measure :

a]45°

b]20°35'

c] 50°38'40"

Solutions

as we know 180°= π radian.

1 degree is equal to = π/180

solution 1]b.

35' = 35/60 hour now, 20+35/60= 247/12 degree

now change in radian 247/12*π/180= 1235/54 grad.

solution 1]c.

40"=40/60minutes now 38+40/60=116/3min.

after converting minutes in hours 116/180 , add all now 50+116/180=2279/45 degree , Now change it to radian , 2279/45*π/180=2279/7290

One angle of a triangle is 54 degree and another is π/4 radian. Find the third angle in centesimal unit i.e. degree

Solution no-2

angle A=54, angle B= π/4rad.

angle B=45degree

total measures of a triangle is 180 degree so to get remaining i.e. third angle We subsctract the sum of Both from 180 degree Ans. 180- 99= 81 degree

Value of 1 rad=57°16'22"

Find the values of

a)sin2295°

b)tan 1500°

c)tan405°

d)sin225°

Solutions.........

a) sin2295°= sin(6*360° +135°) { easy way to get this is to divide by 360° i.e. 2295/360°}

as last day On 27 apr., 2017 i have explained in my post in the first quadrants all the trignometric identities are postive,

Note:- we only take which is left i.e. 135°

sin(135°)= sin (180-45)= sin 45° Ans.......

b.) tan1500°=tan (4*360°+60°)

tan60°

Now you are able to solve

find the value of

Sin(22½)=?

Let θ= 22+1/2

2θ=45

take Cos both the sides

i.e. Cos2θ=cos45

1/√2=1-2sin²22½ {let sin 22½= X)

now 2x²=1-1/√2

by soving it we get the value ,

Find the value of

sin15

sin75

hints 15 can be written as 45-30

and 75 can be written as 45+30

As I said these questions are Basic . But some

*questions are asked by ssc in previous years examination.*__Question 1-__Express the following angles in radian measure and centesimal measure :

a]45°

b]20°35'

c] 50°38'40"

Solutions

*:-**the term ["] is called as seconds & the term ['] is called as minute*solution - 1] a.So, we need to do is that term second should be in minute & the term minute should be in hour (because ° is counted in hour)

as we know 180°= π radian.

1 degree is equal to = π/180

**45**°ℝℙ= 45*π/180= π/4solution 1]b.

35' = 35/60 hour now, 20+35/60= 247/12 degree

now change in radian 247/12*π/180= 1235/54 grad.

solution 1]c.

40"=40/60minutes now 38+40/60=116/3min.

after converting minutes in hours 116/180 , add all now 50+116/180=2279/45 degree , Now change it to radian , 2279/45*π/180=2279/7290

__Question - 2__One angle of a triangle is 54 degree and another is π/4 radian. Find the third angle in centesimal unit i.e. degree

Solution no-2

angle A=54, angle B= π/4rad.

angle B=45degree

total measures of a triangle is 180 degree so to get remaining i.e. third angle We subsctract the sum of Both from 180 degree Ans. 180- 99= 81 degree

Value of 1 rad=57°16'22"

__Question no-3__Find the values of

a)sin2295°

b)tan 1500°

c)tan405°

d)sin225°

Solutions.........

a) sin2295°= sin(6*360° +135°) { easy way to get this is to divide by 360° i.e. 2295/360°}

as last day On 27 apr., 2017 i have explained in my post in the first quadrants all the trignometric identities are postive,

Note:- we only take which is left i.e. 135°

sin(135°)= sin (180-45)= sin 45° Ans.......

b.) tan1500°=tan (4*360°+60°)

tan60°

Now you are able to solve

**of it.***c,d*__SOME OF THE SSC'S MOST IMPORTANT PREVIOIUS YEARS IDENTITIES.__

__QUESTION NO- 4__find the value of

Sin(22½)=?

Let θ= 22+1/2

2θ=45

take Cos both the sides

i.e. Cos2θ=cos45

1/√2=1-2sin²22½ {let sin 22½= X)

now 2x²=1-1/√2

by soving it we get the value ,

if there were cos instead of sin we can change the sign i.e. "+"

__Question no- 5__Find the value of

sin15

sin75

hints 15 can be written as 45-30

and 75 can be written as 45+30

__SO friends thease are the basic question on trigonometry which is being asked in ssc directly of indirectly. trigonometry is vast it can not be done in a day.____THANK YOU KEEP VISITING KEEP LEARNING AFTER THAT TEACH YOUR EXPERIENCE TO THE ONE WHO'S NEEDY OF IT.__
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